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Answer 1 · 2017-04-21T02:25:04

$"Molarity" = 0.53M$ $KClO_3$

$"Molarity"=("moles of the solute")/"volume of the solution" = "moles"/"liters"$

We can begin by converting grams to moles
*The molar mass for $KClO_3$ is $122.55g$

$9.14g$ x $(1 " mole")/(122.55g)$

$9.14cancel(g)$ x $(1 " mole")/(122.55cancel(g)) = 0.0746 " moles"$

We have our moles and we have our volume but note: it's not in $L$ so we must convert $mL$ to $L$

We set up a conversion factor:

$(0.001L)/(1cancel(mL))$ x $(140cancel(mL))/(1)= 0.14L$

Finally, using the formula for molarity given earlier...

$"Molarity"="moles"/"liters"$

$"Molarity" = (0.0746 " moles " KClO_3)/(0.14L)$

$"Molarity" = 0.53M$ $KClO_3$