What mass of caffeine is present in a $2.5L$ volume of solution whose concentration was $1.00mol*L^-1$ with respect to caffeine?

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Answer 1 · 2017-04-21T18:28:00

Approx. $500*g$ .................

We calculate the product...........

$2.5*cancelLxx1.00*cancel(mol*L^-1)xx194.19* g*cancel(mol^-1)=??*g$ .

We have used the relationship:

$"Concentration"="Moles of solute"/"Volume of solution"$ , and thus,

$"Moles of solute"="concentration"xx"volume of solution......."$

What mass of caffeine is present in a 2.5*L2.5*L volume of solution whose concentration was 1.00*mol*L^-11.00*mol*L^-1 with respect to caffeine?