Question

A `5.57*g` mass of propane was combusted `24.1*g` oxygen gas. Can you represent the reaction by means of an equation, and identify the reagent in deficiency?

Answer 1

So we work out the molar quantities of each reagent.......and interrogate the stoichiometric reaction..........

Explanation:

`C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)`

`"Moles of propane"=(5.57*g)/(44.1*g*mol^-1)=0.126*mol`

`"Moles of dioxygen"=(24.1*g)/(32.0*g*mol^-1)=0.753*mol`

And thus there is a SLIGHT stoichiometric excess of dioxygen gas. And `C_3H_8` is the reagent in deficiency.

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