What mass of "calcium carbonate" is equivalent to "Avogadro's number" pf formula units of CaCO_3?

1 Answer
anor277
Apr 23, 2017

A mass of 100.09*g is specified.

Explanation:

6.022xx10^23 units of ANYTHING, specifies 1 mole of that thing, i.e. N_A individual units of that thing...........

And thus in 1*mol of CaCO_3, N_A formula units, there are: N_A Ca atoms; N_A C atoms; and 3xxN_A O atoms.

Because N_A ""^12C atoms have a mass of 12.00*g, and N_A ""^40Ca atoms have a mass of 40.00*g, and N_A ""^16O atoms have a mass of 16.0*g, if we sum the masses appropriately we get a mass of approx. 100*g, per molar quantity. Agreed?

From where did I get these molar masses? From where will YOU get the atomic mass if asked this question is asked of you in a test?

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