The K_"sp" values are of course available in the literature, and SHOULD have been included in the question.
Once we have K_"sp" values, then we can address the various solubility. For calcium chloride we approach this in this manner........
Ca(OH)_2(s) rightleftharpoons Ca^(2+)+2HO^-
Now K_"sp"=[Ca^(2+)][HO^-]^2.
And if we call the solubility of calcium chloride, S, then S=[Ca^(2+)], and [Cl^-]=2S (provided there is no extraneous source of calcium and chloride ions......)
So K_"sp"=Sxx(2S)^2=4S^3.
And S=""^3sqrt((K_"sp")/4).
And so without K_"sp" we are at an impasse. Such calculations require prior measurement or reference to the literature data.