What are the molar ratios of reactants and products in dinitrogen reduction by dihydrogen?

1 Answer
May 1, 2017

Well, "dinitrogen : dihydrogen : ammonia = 1 : 3 : 2".dinitrogen : dihydrogen : ammonia = 1 : 3 : 2.

Explanation:

And thus the molar ratio follows the given stoichiometry of the reaction:

N_2 + 3H_2(g) rarr 2NH_3(g)N2+3H2(g)2NH3(g)