Question #b21cc

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Question #b21cc

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Answer 1 · 2017-04-26T23:01:52

$d e n s i t y = 1.95 \frac{g}{L}$ $density = 1.95 g/L$

Explanation:

Use these 2 formulas:

$P V = n R T$ $PV = nRT$

$m o l s = \frac{g}{m m}$ $mols = g/(mm)$

Note: mm is molar mass

Combine them to get:

$P V = \frac{g}{m m} R T$ $PV = g/(mm)RT$

Since you are trying to solve for g/L, rearrange the formula:

$\frac{g}{V} = \frac{P \cdot m m}{R T}$ $g/V = (P*mm)/(RT)$

$\frac{g}{V} = \frac{(3.00 a t m) \cdot (16.04 \frac{g}{m o l})}{(0.08206 \frac{L \cdot a t m}{K \cdot m o l}) (301 K)}$ $g/V = ((3.00atm)*(16.04g/(mol)))/((0.08206(L*atm)/(K*mol))(301K))$

$\frac{g}{V} = 1.948173405$ $g/V = 1.948173405$

Since you only have 3 sig figs, the answer would be:

$d e n s i t y = 1.95 \frac{g}{L}$ $density = 1.95 g/L$

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Question #b21cc

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