What is the molarity of 98% H2SO4?

1 Answer
Truong-Son N.
Apr 28, 2017

Then that means you have 0.98 L H2SO4 in 1 L solution, for instance. Let's assume we are at 298.15 K. Then, assuming the density of 98% v/v H2SO4 is approximately the same as pure H2SO4, we have:

0.98 L H2SO4×1.84 gmL×1000 mLL≈1803.2 g

and the mols of it would be:

1803.2 g H2SO4×1 mol98.079 g=18.39 mols H2SO4

Therefore, the concentration is:

18.39 mols H2SO41 L solution≈18.4 M

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