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Answer 1 · 2017-05-03T19:47:06

The specific heat capacity of the material is ${0.6469 J\cdot°C}^{-1} g^{-1}$ $"0.6469 J·°C"^"-1""g"^"-1"$ .

The formula for the amount heat $q$ $q$ absorbed by a substance is

$color(blue)(bar(ul(|color(white)(a/a)q = mCΔTcolor(white)(a/a)|)))" "$

where

$m$ is the mass of the substance
$C$ is the specific heat capacity of the material
$ΔT$ is the temperature change

You can rearrange the formula to calculate the specific heat capacity:

$C = q/(mΔT)$

In this problem,

$q = "-86 285 J"$
$m = "863.3 g"$
$ΔT = "(25.00 - 179.5) °C" = "-154.5 °C"$

∴ $C = "-86 285 J"/"863.3 g × (-154.5 °C)" = "0.6469 J·°C"^"-1""g"^"-1"$

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