How many neutrons are present in a $54 \cdot m L$ $54*mL$ volume of $^{1} H_{2}^{16} O$ $""^(1)H_2""^(16)O$ under standard conditions?

Question

How many neutrons are present in a $54 \cdot m L$ $54*mL$ volume of $^{1} H_{2}^{16} O$ $""^(1)H_2""^(16)O$ under standard conditions?

1 Answer

Impact of this question

1841 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-30T14:22:06

Approx... $24 \cdot N_{A}$ $24*N_A$ .........

Explanation:

Each individual water molecule, $^{1} H_{2}^{16} O$ $""^(1)H_2""^(16)O$ molecule contains $8 neutrons$ $"8 neutrons"$ (of course for this problem we ignore isotopic distribution, and these all are contained in the oxygen nucleus.

And so $number of neutrons$ $"number of neutrons"$

$= 8 neutrons \times \frac{54 \cdot m L \times 1.00 \cdot g \cdot m L^{- 1}}{18.01 \cdot g \cdot m o l^{- 1}} \times N_{A}$ $="8 neutrons"xx(54*mLxx1.00*g*mL^-1)/(18.01*g*mol^-1)xxN_A$ ,

where $N_{A} = Avocado Number = 6.022 \times 10^{23} \cdot m o l^{- 1}$ $N_A="Avocado Number"=6.022xx10^23*mol^-1$

$= 24 \cdot N_{A}$ $=24*N_A$ .

And here I use $N_{A}$ $N_A$ as I would any other collective number, $dozen, score, gross$ $"dozen, score, gross"$ etc. I am certainly free to do so, and any other chemist would immediately appreciate the quantity.

Science

Math

Humanities

... and beyond

How many neutrons are present in a $54 \cdot m L$ $54*mL$ volume of $^{1} H_{2}^{16} O$ $""^(1)H_2""^(16)O$ under standard conditions?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How many neutrons are present in a 54⋅mL54*mL volume of 1H216O""^(1)H_2""^(16)O under standard conditions?

1 Answer

Explanation:

Related questions

Impact of this question

How many neutrons are present in a $54 \cdot m L$ $54*mL$ volume of $^{1} H_{2}^{16} O$ $""^(1)H_2""^(16)O$ under standard conditions?