Question #9c009

1 Answer
anor277
May 1, 2017

Well, [Na^+] has a 0.400*mol*L^-1 concentration..........

Explanation:

The concentration of Na_2SO_4 was specified to be 0.200*mol*L^-1. Because the formula contains two equiv of sodium ion, [Na^+]=2xx0.200*mol*L^-1=0.400*mol*L^-1 WITH RESPECT TO SODIUM IONS. Do you see what's going on?

What is the concentration of nitrate ions in 0.100*mol*L^-1 Ca(NO_3)_2(aq)? Is it different from [Ca^(2+)]??

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