What mass of anhydrous salt is required to prepare a $50g$ mass of $"acetic acid trihydrate"$ , $H_3C-CO_2H3H_2O$ ?

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Answer 1 · 2017-05-05T07:36:32

You want approx. $30*g$ of the anhydrous salt.

Sodium acetate trihydrate has a formula mass of $136.04*g*mol^-1$ .

And thus a $50*g$ mass is a molar quantity of..........

$(50*cancelg)/(136.04*cancelg*mol^-1)=0.368*1/(1/(mol))=0.368*mol.$

Now this is $0.368*mol$ with respect to sodium and acetate ions, but $1.10*mol$ with respect to water.

And so we use the given molar quantity to calculate an equivalent mass of the ANHYDROUS salt:

$0.368*cancel(mol)xx82.03*g*cancel(mol^-1)=30.2*g$

What mass of anhydrous salt is required to prepare a 50*g50*g mass of "acetic acid trihydrate""acetic acid trihydrate", H_3C-CO_2H*3H_2OH_3C-CO_2H*3H_2O?