A $66.5g$ mass of a solute whose formula mass is $80.05gmol^-1$ is used to prepare a solution of $315mL$ volume. What is its molarity?

Question

2025 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-05T18:51:10

$"Molarity"~=2.7*mol*L^-1$

We want the quotient, $"moles of stuff (mol)"/"volume of solution (L)"$ to give the $"molarity"$ .

And thus $((66.5*g)/(80.05*g*mol^-1))/(315*mLxx10^-3*L*mL^-1)~=2.7*mol*L^-1$

A 66.5*g66.5*g mass of a solute whose formula mass is 80.05*g*mol^-180.05*g*mol^-1 is used to prepare a solution of 315*mL315*mL volume. What is its molarity?