Question

A `2.5*L` volume of gas at `800*mm*Hg` pressure, is expanded with constant temperature to a `5.0*L` volume. What is the resultant pressure of the gas?

Answer 1

Well `P_1V_1=P_2V_2...........` given constant `T`, which is old `"Boyle's Law".................`

Explanation:

And so `P_2=(P_1V_1)/V_2=(800*mm*Hgxx0.250*L)/(0.500*L)=`

`400*mm*Hg`.

Just to ADD that you DO NOT measure a pressure in `mm*Hg` OVER `1*atm` (`1*atm-=760*mm*Hg`). This is an inappropriate question posed by someone who has NEVER used a mercury manometer, and certainly NEVER cleaned up a mercury spill.