A 2.5*L2.5⋅L volume of gas at 800*mm*Hg800⋅mm⋅Hg pressure, is expanded with constant temperature to a 5.0*L5.0⋅L volume. What is the resultant pressure of the gas?

1 Answer
anor277
May 8, 2017

Well P_1V_1=P_2V_2........... given constant T, which is old "Boyle's Law".................

Explanation:

And so P_2=(P_1V_1)/V_2=(800*mm*Hgxx0.250*L)/(0.500*L)=

400*mm*Hg.

Just to ADD that you DO NOT measure a pressure in mm*Hg OVER 1*atm (1*atm-=760*mm*Hg). This is an inappropriate question posed by someone who has NEVER used a mercury manometer, and certainly NEVER cleaned up a mercury spill.

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