What is $K_{2}$ $K_2$ ...for $2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$ ?

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What is $K_{2}$ $K_2$ ...for $2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$ ?

Given.... $2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$
....for which $K_{1} = 6$ $K_1=6$ ...what is $K_{2}$ $K_2$ for the reaction...
$2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$ ?:
$A .$ $A.$ $K_{2} = 36$ $K_2=36$ ; $B .$ $B.$ $K_{2} = 6$ $K_2=6$ ; $C .$ $C.$ $unknown$ $"unknown"$ ; $D .$ $D.$ $2.50$ $2.50$ ?

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Answer 1 · 2017-05-09T17:25:39

$Option D$ $"Option D"$

Explanation:

For $2 C O (g) + O_{2} (g) \to 2 C O_{2} (g)$ $2CO(g) + O_2(g) rarr 2CO_2(g)$

We have $K_{c 1} = 6 = \frac{{[C O_{2}]}_{2}^{2}}{[O_{2}] {[C O]}^{2}}$ $K_(c1)=6=([CO_2]^2)/([O_2][CO]^2)$

But for...........

$C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)$ $CO(g) + 1/2O_2(g) rarr CO_2(g)$

We have $K_{c 2} = \frac{[C O_{2} (g)]}{[C O] {[O_{2}]}_{2}^{\frac{1}{2}}}$ $K_(c2)=([CO_2(g)])/([CO][O_2]^(1/2))$

But $K_{c 2} = \sqrt{\frac{{[C O_{2}]}_{2}^{2}}{[O_{2}] {[C O]}^{2}}} = \sqrt{K_{c1}} = \sqrt{6} = 2.45$ $K_(c2)=sqrt(([CO_2]^2)/([O_2][CO]^2))=sqrt(K_"c1")=sqrt(6)=2.45$ , close enuff to $D .$ $D.$

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What is $K_{2}$ $K_2$ ...for $2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$ ?

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What is K2K_2...for 2CO(g)+O2(g)⇌2CO2(g)2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)?

Given....2CO(g)+O2(g)⇌2CO2(g)2CO(g) + O_2(g) rightleftharpoons 2CO_2(g) ....for which K1=6K_1=6...what is K2K_2 for the reaction... 2CO(g)+O2(g)⇌2CO2(g)2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)?: A.A. K2=36K_2=36; B.B. K2=6K_2=6; C.C. unknown"unknown"; D.D. 2.502.50?

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What is $K_{2}$ $K_2$ ...for $2 C O (g) + O_{2} (g) ⇌ 2 C O_{2} (g)$ $2CO(g) + O_2(g) rightleftharpoons 2CO_2(g)$ ?