If the $empirical formula$ $"empirical formula"$ is $C H$ $CH$ , and the molecular mass is $26 \cdot g \cdot m o l^{- 1}$ $26gmol^-1$ , what is the $molecular formula$ $"molecular formula"$ ?

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If the $empirical formula$ $"empirical formula"$ is $C H$ $CH$ , and the molecular mass is $26 \cdot g \cdot m o l^{- 1}$ $26gmol^-1$ , what is the $molecular formula$ $"molecular formula"$ ?

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Answer 1 · 2017-05-09T21:19:26

The molecular formula is always a whole number of the empirical formula...........

Explanation:

............and of course the multiple may be one.

And thus $molecular formula = n \times empirical formula$ $"molecular formula"="n"xx"empirical formula"$

And so the given molecular mass is $26 \cdot g \cdot m o l^{- 1}$ $26*g*mol^-1$ .

And so $26 \cdot g \cdot m o l^{- 1} = n \times (12.0 \cdot g + \times 1 \cdot g)$ $26*g*mol^-1=nxx(12.0*g+xx1*g)$

Clearly, $n = 2$ $n=2$ , and the molecular formula is $C_{2} H_{2}$ $C_2H_2$ , which is good because of course we know that $acetylene = H - C \equiv C - H$ $"acetylene"=H-C-=C-H$ , i.e. two degrees of unsaturation.

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If the $empirical formula$ $"empirical formula"$ is $C H$ $CH$ , and the molecular mass is $26 \cdot g \cdot m o l^{- 1}$ $26gmol^-1$ , what is the $molecular formula$ $"molecular formula"$ ?

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If the empirical formula"empirical formula" is CHCH, and the molecular mass is 26⋅g⋅mol−126*g*mol^-1, what is the molecular formula"molecular formula"?

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If the $empirical formula$ $"empirical formula"$ is $C H$ $CH$ , and the molecular mass is $26 \cdot g \cdot m o l^{- 1}$ $26gmol^-1$ , what is the $molecular formula$ $"molecular formula"$ ?