Question #90724

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Answer 1 · 2017-05-13T13:12:22

You figure out the amount of $O_{2}$ $"O"_2$ to react with 1 mol of $H$ $"H"$ atoms.

We can define an equivalent as the amount of a substance that can combine with or displace one mole of hydrogen atoms.

However, the number of equivalents depends on the reaction involved.

Consider this reaction.

${2H}_{2} + O_{2} \to 2 H_{2} O$ $"2H"_2 + "O"_2 → 2"H"_2"O"$

It takes 4 mol of $H$ $"H"$ atoms to react with 1 mol of $O_{2}$ $"O"_2$ .

So, 1 mol of $H$ $"H"$ atoms reacts with 0.25 mol of $O_{2}$ $"O"_2$ .

∴ 1 eq of $O_{2}$ $"O"_2$ = 0.25 mol of $O_{2}$ $"O"_2$ .

Now, consider this reaction.

$H_{2} + O_{2} \to H_{2} O_{2}$ $"H"_2 + "O"_2 → "H"_2"O"_2$

It takes 2 mol of $H$ $"H"$ atoms to react with 1 mol of $O_{2}$ $"O"_2$ .

So, 1 mol of $H$ $"H"$ atoms reacts with 0.5 mol of $O_{2}$ $"O"_2$ .

In this reaction, 1 eq of $O_{2}$ $"O"_2$ = 0.5 mol of $O_{2}$ $"O"_2$ .