Question #ab462

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Question #ab462

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Answer 1 · 2017-05-15T15:17:38

$= 2 x \sqrt{3 x y} + 3 x \sqrt{2 y}$ $= 2xsqrt(3xy) +3xsqrt(2y)$

Explanation:

Write each term under a root as the product of its factors, using squares where possible.

$\sqrt{12 x^{3} y} - x \sqrt{50 y} + \sqrt{128 x^{2} y}$ $sqrt(12x^3y) -xsqrt(50y) +sqrt(128x^2y)$

$= \sqrt{4 \times 3 \times x^{2} \times x y} - x \sqrt{25 \times 2 y} + \sqrt{64 \times 2 x^{2} y}$ $= sqrt(4 xx 3 xx x^2 xx xy) -xsqrt(25xx2y) +sqrt(64 xx2x^2y)$

Find the square roots where possible.

$= 2 x \sqrt{3 x y} - 5 x \sqrt{2 y} + 8 x \sqrt{2 y}$ $= 2xsqrt(3xy) -5xcolor(blue)(sqrt(2y)) +8xcolor(blue)(sqrt(2y))$

Add the like terms:

$= 2 x \sqrt{3 x y} + 3 x \sqrt{2 y}$ $= 2xsqrt(3xy) +3xsqrt(2y)$

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Question #ab462

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