How many oxygen ATOMS are present in a 25*g mass of aluminum phosphate?

1 Answer
anor277
May 25, 2017

Approx. 0.82xxN_A oxygen atoms, where N_A=6.022xx10^23.

Explanation:

"Moles of aluminium phosphate"=(25*g)/(121.95*g*mol^-1)

=0.205*mol

But given the molar quantity, and given the stoichiometry of AlPO_4, there are 4xx0.205*mol=0.820*mol of "oxygen atoms", i.e. 0.820*molxx6.022xx10^23*mol^-1=?? oxygen atoms...

What mass of oxygen does this molar quantity represent.

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