Question #742bc

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Question #742bc

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Answer 1 · 2017-05-28T01:04:28

b. 120'K

Explanation:

Start with the Ideal Gas Law: $P \cdot V = (n \cdot R \cdot T)$ $P*V = (n*R*T)$
Rearranging the Ideal Gas Law equation we have $T = \frac{P \cdot V}{n \cdot R}$ $T = (P*V)/(n*R)$

V = 100.0 L
R = 0.0820575 L-atm/K-mol
28kg = 28000g
n = (28000g/28.0 g/mol) = 1000 moles of $N_{2}$ $N_2$ .
$P = (1 x 10^{7} P a) \cdot (\frac{1 atm}{101325} P a)$ $P = (1 x 10^7 Pa) * ((1 "atm")/101325 Pa)$ = 98.7 atm
$T = \frac{98.7 \cdot 100}{0.0821 \cdot 1000}$ $T = (98.7*100)/(0.0821*1000)$ = 120 ‘K

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Question #742bc

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