What mass of $C r {(N O_{3})}_{3} \cdot 9 H_{2} O$ $Cr(NO_3)_39H_2O$ is required to make a $100 \cdot m L$ $100mL$ volume of a solution that is $2.00 \times 10^{- 3} \cdot m o l \cdot L^{- 1}$ $2.00xx10^-3molL^-1$ with respect to $C r^{3 +}$ $Cr^(3+)$ ?

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What mass of $C r {(N O_{3})}_{3} \cdot 9 H_{2} O$ $Cr(NO_3)_39H_2O$ is required to make a $100 \cdot m L$ $100mL$ volume of a solution that is $2.00 \times 10^{- 3} \cdot m o l \cdot L^{- 1}$ $2.00xx10^-3molL^-1$ with respect to $C r^{3 +}$ $Cr^(3+)$ ?

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Answer 1 · 2017-05-28T20:12:27

We need a mass of approx... $0.8 \cdot g$ $0.8*g$

Explanation:

We use the relationship, $Concentration = \frac{Moles of solute}{Volume of solution}$ $"Concentration"="Moles of solute"/"Volume of solution"$ ,

and thus to get the $moles of solute$ $"moles of solute"$ , we take the product............

$Moles of solute = Concentration \times Volume$ $"Moles of solute"="Concentration"xx"Volume"$

$= 100.0 \cdot m L \times 10^{- 3} \cdot L \cdot m L^{- 1} \times 0.0200 \cdot m o l \cdot L^{- 1}$ $=100.0*mLxx10^-3*L*mL^-1xx0.0200*mol*L^-1$

$= 2.000 \times 10^{- 3} \cdot m o l$ $=2.000xx10^-3*mol$ .

And this represents a mass of...............

$= 2.000 \times 10^{- 3} \cdot m o l \times 400.15 \cdot g \cdot m o l^{- 1} = 0.800 \cdot g$ $=2.000xx10^-3*molxx400.15*g*mol^-1=0.800*g$ .

Note that this question has been poorly specified. When you say $chromium nitrate nonahydrate$ $"chromium nitrate nonahydrate"$ I have ASSUMED that you mean the $C r (+ I I I)$ $Cr(+III)$ hydrate, $C r {(N O_{3})}_{3} \cdot 9 H_{2} O$ $Cr(NO_3)_3*9H_2O$ , whose formula mass is $400.15 \cdot g \cdot m o l^{- 1}$ $400.15*g*mol^-1$ .

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What mass of $C r {(N O_{3})}_{3} \cdot 9 H_{2} O$ $Cr(NO_3)_39H_2O$ is required to make a $100 \cdot m L$ $100mL$ volume of a solution that is $2.00 \times 10^{- 3} \cdot m o l \cdot L^{- 1}$ $2.00xx10^-3molL^-1$ with respect to $C r^{3 +}$ $Cr^(3+)$ ?

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What mass of Cr(NO3)3⋅9H2OCr(NO_3)_3*9H_2O is required to make a 100⋅mL100*mL volume of a solution that is 2.00×10−3⋅mol⋅L−12.00xx10^-3*mol*L^-1 with respect to Cr3+Cr^(3+)?

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What mass of $C r {(N O_{3})}_{3} \cdot 9 H_{2} O$ $Cr(NO_3)_39H_2O$ is required to make a $100 \cdot m L$ $100mL$ volume of a solution that is $2.00 \times 10^{- 3} \cdot m o l \cdot L^{- 1}$ $2.00xx10^-3molL^-1$ with respect to $C r^{3 +}$ $Cr^(3+)$ ?