What molar quantity of $H C l$ $HCl$ is present in a $23.6 \cdot c m^{3}$ $23.6cm^3$ volume of $0.1 \cdot m o l \cdot L^{- 1}$ $0.1mol*L^-1$ concentration?

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What molar quantity of $H C l$ $HCl$ is present in a $23.6 \cdot c m^{3}$ $23.6cm^3$ volume of $0.1 \cdot m o l \cdot L^{- 1}$ $0.1mol*L^-1$ concentration?

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Answer 1 · 2017-05-29T19:41:01

You need to quote the $density$ $"density"$ , $ρ$ $rho$ , of the acid solution..........

Explanation:

As a matter of fact, the density of this (fairly dilute) acid would be very close to that of water, i.e. $ρ = 1 \cdot g \cdot c m^{- 3}$ $rho=1*g*cm^-3$ . However, we need it to get the volume of the acid............and THEN we can calculate the number of moles this mass of solution contains quite precisely.

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What molar quantity of $H C l$ $HCl$ is present in a $23.6 \cdot c m^{3}$ $23.6cm^3$ volume of $0.1 \cdot m o l \cdot L^{- 1}$ $0.1mol*L^-1$ concentration?

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What molar quantity of HClHClHCl is present in a 23.6*cm^323.6⋅cm323.6*cm^3 volume of 0.1*mol*L^-10.1⋅mol⋅L−10.1*mol*L^-1 concentration?

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What molar quantity of $H C l$ $HCl$ is present in a $23.6 \cdot c m^{3}$ $23.6cm^3$ volume of $0.1 \cdot m o l \cdot L^{- 1}$ $0.1mol*L^-1$ concentration?