A gas occupies "0.5650 L"0.5650 L in a closed container. The initial pressure is "______"______ if the volume increases to "1.204 L"1.204 L at a pressure of "715.1 bar"715.1 bar?

1 Answer
Jun 2, 2017

The initial pressure, which goes in the blank, was "1524 bar"1524 bar.

Explanation:

This question involves Boyle's gas law , which states that the volume of a given amount of a gas varies inversely with the pressure, as long as temperature is kept constant. This means that when the volume increases, the pressure decreases, and vice-versa. The equation you will need to answer this question is:

P_1V_1=P_2V_2P1V1=P2V2

In your question, the blank is the initial pressure, P_1P1, whis is your unknown. Organize the rest of the data.

Known

V_1="0.5650 L"V1=0.5650 L

P_2="715.1 bar"P2=715.1 bar

V_2="1.204 L"V2=1.204 L

Solution

Rearrange the equation above to isolate P_1P1. Insert the known data into the equation and solve.

P_1=(P_2V_2)/(V_1)P1=P2V2V1

P_1=(715.1"bar"xx1.204color(red)cancel(color(black)("L")))/(0.5650color(red)cancel(color(black)("L")))="1524 bar" (rounded to four sig figs)