How many moles of oxygen are there in a 1.05⋅mmol quantity of aluminum nitrate?

1 Answer
anor277
Jun 2, 2017

There are 9.45⋅mmol of oxygen atoms.............

Explanation:

Clearly, 1⋅mol Al(NO3)3 contains 9⋅mol of oxygen atoms, i.e. 9×NA oxygen atoms, where NA=Avogadro's Number ≡ 6.022×1023⋅mol−1.

And thus in a 1.05⋅mmol quantity of aluminum nitrate, there are 9×1.05×10−3⋅mol×6.022×1023⋅mol−1=?? oxygen atoms

What is the mass of this molar quantity?

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