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Question #5dbc6

1 Answer

Jun 2, 2017

1.5 mol of $K M n O_{4}$ $KMnO_4$ (237 grams)

Explanation:

First find molecular mass of potassium permanganate:

K=39
Mn=55
O=16

$M W = 39 + 55 + 4 \cdot 16 = 158 g r a m s$ $MW=39+55+4*16=158 grams$ per mol

Since you have 1.5 mol, just multiply these two numbers

Your answer is $1.5 \cdot 158 = 237$ $1.5*158=237$ grams

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