Question #a4cd9

1 Answer
Jun 3, 2017

No ppt forms ... K_"sp" (=2.4 x 10^-5) > Q_"sp"(1.6x10^-5)

Explanation:

20ml(0.01MCaCl_2) + 20ml(0.008MNa_2SO_4)
=> (0.02)(0.01)"mole" CaCl_2 + (0.02)(0.008)"mole" Na_2SO_4
=> 0.0002"mole" CaCl_2 + 0.00016"mole"Na_2SO_4

=> Na_2SO_4 is the limiting reagent => 1.6x10^-4" mole CaSO_4

[CaSO_4] = 1.6x10^-4" "mole" CaSO_4 / "0.040L Solution" = 0.004M

0.004MCaSO_4 rightleftharpoons +0.004M(Ca^(+2)) + 0.004M(SO_4^(2-))

Q_(sp) = [Ca^(+3)][SO_4^(2-)] = (0.004M)(0.004M) = 1.6x10^-5

K_(sp)=2.4x10^-5 > Q_(sp) = 1.6x10^-5 => No Ppt will form.