How would I determine how many grams of antimony would form from the reaction of carbon with $3.6 g$ $"3.6 g"$ of antimony(III) oxide?

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How would I determine how many grams of antimony would form from the reaction of carbon with $3.6 g$ $"3.6 g"$ of antimony(III) oxide?

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Answer 1 · 2017-06-04T21:03:34

Use dimensional analysis (a.k.a. the factor-label method)

Explanation:

given: $3.6 g S b_{2} O_{3}$ $3.6"g "Sb_2O_3$
reacts with carbon (C)
want: mass of Sb

$S b_{2} O_{3} + 3 C \to 2 S b + 3 C O$ $Sb_2O_3 + 3C rarr 2Sb + 3CO$

Setup a Dimensional analysis starting with the given over 1:

$\frac{3.6 g S b_{2} O_{3}}{1}$ $(3.6"g "Sb_2O_3)/1$

Multiply by the molar mass conversion factor for $S b_{2} O_{3}$ $Sb_2O_3$ :

$\frac{3.6 g S b_{2} O_{3}}{1} \frac{1 mol S b_{2} O_{3}}{291.5 g S b_{2} O_{3}}$ $(3.6"g "Sb_2O_3)/1(1"mol "Sb_2O_3)/(291.5"g "Sb_2O_3)$

From the equation we see that 1 mole of $S b_{2} O_{3}$ $Sb_2O_3$ produces 2 moles of $S b$ $Sb$ so we multiply by that conversion factor:

$\frac{3.6 g S b_{2} O_{3}}{1} \frac{1 mol S b_{2} O_{3}}{291.5 g S b_{2} O_{3}} \frac{2 mol S b}{1 mol S b_{2} O_{3}}$ $(3.6"g "Sb_2O_3)/1(1"mol "Sb_2O_3)/(291.5"g "Sb_2O_3)(2"mol "Sb)/(1"mol "Sb_2O_3)$

Multiply by the conversion factor for the molar mass of $S b$ $Sb$ :

$\frac{3.6 g S b_{2} O_{3}}{1} \frac{1 mol S b_{2} O_{3}}{291.5 g S b_{2} O_{3}} \frac{2 mol S b}{1 mol S b_{2} O_{3}} \frac{121.76 g S b}{1 mol S b}$ $(3.6"g "Sb_2O_3)/1(1"mol "Sb_2O_3)/(291.5"g "Sb_2O_3)(2"mol "Sb)/(1"mol "Sb_2O_3)(121.76"g "Sb)/(1"mol "Sb)$

Please observe that the units cancel; leaving only the units $g S b$ $"g "Sb$

$\frac{3.6 g S b_{2} O_{3}}{1} \frac{1 mol S b_{2} O_{3}}{291.5 g S b_{2} O_{3}} \frac{2 mol S b}{1 mol S b_{2} O_{3}} \frac{121.76 g S b}{1 mol S b} = 3.0 g S b \leftarrow$ $(3.6"g "Sb_2O_3)/1(1"mol "Sb_2O_3)/(291.5"g "Sb_2O_3)(2"mol "Sb)/(1"mol "Sb_2O_3)(121.76"g "Sb)/(1"mol" Sb) = 3.0"g "Sb larr$
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How would I determine how many grams of antimony would form from the reaction of carbon with $3.6 g$ $"3.6 g"$ of antimony(III) oxide?

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Explanation:

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How would I determine how many grams of antimony would form from the reaction of carbon with "3.6 g"3.6 g"3.6 g" of antimony(III) oxide?

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Explanation:

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How would I determine how many grams of antimony would form from the reaction of carbon with $3.6 g$ $"3.6 g"$ of antimony(III) oxide?