Question #0a813

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Question #0a813

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Answer 1 · 2017-06-10T11:16:42

Balanced equation of the redox reaction

$M n O_{2} + 4 H C l \to M n C l_{2} + C l_{2} + 2 H_{2} O$ $MnO_2+4HCl->MnCl_2+Cl_2+2H_2O$

This equation reveals that 4mol $H C l$ $HCl$ produces 1mol $C l_{2}$ $Cl_2$

We have been given 400 mL or 0.4L of 0.1 M HCl which contains $0.4 \times 0.1 m o l = 0.04 m o l$ $0.4xx0.1mol=0.04mol$ $H C l$ $HCl$

Hence the amount of $C l_{2}$ $Cl_2$ produced $\frac{1}{4} \times 0.04 = 0.1 m o l = 0.71 g$ $1/4xx0.04=0.1mol=0.71g" "$ as the molar mass of $C l_{2} = 71 g / m o l$ $Cl_2=71g"/"mol$

The density of $C l_{2} = 2.84 g / L$ $Cl_2=2.84g"/"L$

So its volume will be $\frac{0.71}{2.84} L = 0.25 L$ $0.71/2.84L=0.25L$

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