A $5 \cdot L$ $5L$ volume of gas exerts a pressure of $124 \cdot k P a$ $124kPa$ . How should volume evolve if pressure is increased to $206 \cdot k P a$ $206*kPa$ ?

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A $5 \cdot L$ $5L$ volume of gas exerts a pressure of $124 \cdot k P a$ $124kPa$ . How should volume evolve if pressure is increased to $206 \cdot k P a$ $206*kPa$ ?

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Answer 1 · 2017-06-10T19:16:33

Well $P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$ ....so $V_{2} = 3.0 \cdot L$ $V_2=3.0*L$

Explanation:

Old $Boyle's Law$ $"Boyle's Law"$ holds that for a given quantity gas, $P \propto \frac{1}{V}$ $Pprop1/V$ , and thus $P = \frac{k}{V}$ $P=k/V$ , where $k$ $k$ is some (unspecified!) constant.

And if we solve for $k$ $k$ under different conditions of pressure and volume (with temperature CONSTANT!), then.......

$V_{2} = \frac{P_{1} \times V_{1}}{P_{2}} = \frac{5 \cdot L \times 124 \cdot k P a}{206 \cdot k P a} = 3.00 \cdot L$ $V_2=(P_1xxV_1)/(P_2)=(5*Lxx124*kPa)/(206*kPa)=3.00*L$

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?

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A $5 \cdot L$ $5L$ volume of gas exerts a pressure of $124 \cdot k P a$ $124kPa$ . How should volume evolve if pressure is increased to $206 \cdot k P a$ $206*kPa$ ?

1 Answer

Explanation:

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A 5⋅L5*L volume of gas exerts a pressure of 124⋅kPa124*kPa. How should volume evolve if pressure is increased to 206⋅kPa206*kPa?

1 Answer

Explanation:

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A $5 \cdot L$ $5L$ volume of gas exerts a pressure of $124 \cdot k P a$ $124kPa$ . How should volume evolve if pressure is increased to $206 \cdot k P a$ $206*kPa$ ?