A 5L volume of gas exerts a pressure of 124kPa. How should volume evolve if pressure is increased to 206kPa?

1 Answer
Jun 10, 2017

Well P1V1=P2V2....so V2=3.0L

Explanation:

Old Boyle's Law holds that for a given quantity gas, P1V, and thus P=kV, where k is some (unspecified!) constant.

And if we solve for k under different conditions of pressure and volume (with temperature CONSTANT!), then.......

V2=P1×V1P2=5L×124kPa206kPa=3.00L

Is this answer consistent with the parameters of the problem? Should volume DECREASE with INCREASED pressure?