Question

What is the molarity of concentrated nitric acid that has `rho=1.41*g*mL^-1`, and is `70%` concentrated, `"m/m"`?

Answer 1

`"Concentration"~=16*mol*L^-1`

Explanation:

We want the expression `"Moles"/"Volume of solution"`, and if we take a `1*mL` volume of nitric acid, with a mass of `1.41*g`, then......

`"Concentration"="Moles"/"Volume"` And we use the percentage and density to find the actual mass of nitric acid solute in (for instance) a `1*mL` volume.

`=((70.0%xx1.41*g)/(63.01*g*mol^-1))/(1*mLxx10^-3*L*mL^-1)=??*mol*L^-1`.