How many formula units are in a 17.2*g17.2g mass of magnesium chloride?

1 Answer
Jun 15, 2017

We know that the molar mass of "magnesium chloride"magnesium chloride is 95.21*g95.21g.

Explanation:

And what does this mean? Well, the mass of "Avogadro's Number"Avogadro's Number, i.e. 6.022xx10^236.022×1023 of INDIVIDUAL MgCl_2MgCl2 formula units have a mass of 95.21*g95.21g. And thus the mole is the link between the micro world of atoms and molecules, that which we cannot observe but whose existence we cannot infer, with the macro world of litres, grams, and kilograms.........

And this is the principle of chemical equivalence. We divide the mass by the molar mass, and multiply the resultant "molar"molar quantity by the "Avocado number"Avocado number we gets.......

(17.2*cancel(g))/(95.21*cancelg*cancel(mol^-1))xx6.022xx10^23*cancel(mol^-1)=1.09xx10^23*"formula units" (a number as required).

How many ATOMS are these in this quantity?