Which of the following has the largest number of oxygen atoms?

a)a) 3.65 xx 10^203.65×1020 molecules of "SO"_2SO2
b)b) 3.65 xx 10^203.65×1020 molecules of "SO"_3SO3
c)c) "0.0553 g SO"_30.0553 g SO3
d)d) 5.06 xx 10^(-3) "mols SO"_35.06×10−3mols SO3

1 Answer
Andrea B. · Ernest Z. · Truong-Son N.
Jul 6, 2017

The biggest amount of oxygen is in "5,06" × 10^"-3"5,06×10-3 mol.

Explanation:

Since a mol is 6,02 xx 10^236,02×1023 molecules, you have (3,65 xx 10^20)/ (6,02 xx 10^23)= 6,06 xx 10 ^(-4) 3,65×10206,02×1023=6,06×10−4 mol each of SO_2SO2 and SO_3SO3.

Obviously, there are more oxygen atoms in SO_3SO3.

Furthermore, since the MM of SO_3SO3 is 80.1 g/mol you have (0,0553 g)/(80.1 g/(mol)) = 6,90 xx 10^(-4) mol SO_30,0553g80.1gmol=6,90×10−4molSO3.

Then, the bigger amount of oxygen is in the 0,0553 g of SO_3SO3 where there is a bigger number of moles.

And "5,06" × 10^"-3"5,06×10-3 mol of SO_3SO3 contains even more moles than 0,0553 g of SO_3SO3.

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