At an altitude for which ambient pressure is 0.700*atm0.700⋅atm, and a temperature of 270.15*K270.15⋅K, a balloon contains 3.00*mol3.00⋅mol of gas... What is the volume of the balloon....?

1 Answer
anor277
Jun 18, 2017

There is no question here, but your neighbour, the balloonist, has filled a balloon with approx. 100*L100⋅L volume.

Explanation:

Of course, he may have heated the contents of the balloon somehow, but we must assume T=270*KT=270⋅K, so..........

V=(nRT)/P=(3.00*molxx0.0821*(L*atm)/(K*mol)xx270.15*K)/(0.700*atm)V=nRTP=3.00⋅mol×0.0821⋅L⋅atmK⋅mol×270.15⋅K0.700⋅atm

~=100*L.≅100⋅L.

We have assumed the temperature, and know that the balloon expanded against a 0.700*atm0.700⋅atm pressure. Because the balloon is apparently floating, what is the probable filling gas?

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