What is tan(arccos(sqrt2/2))tan(arccos(√22))? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties 1 Answer Monzur R. Jun 18, 2017 tan(Arccos(sqrt2/2))=1tan(arccos(√22))=1 Explanation: We know that cos(1/4pi) = sqrt2/2 therefore Arccos(sqrt2/2) =1/4pi thereforetan(arccos (sqrt2/2)) = tan(1/4pi)=1 Answer link Related questions How do you use the properties of inverse trigonometric functions to evaluate tan(arcsin (0.31))? What is \sin ( sin^{-1} frac{sqrt{2}}{2})? How do you find the exact value of \cos(tan^{-1}sqrt{3})? How do you evaluate \sec^{-1} \sqrt{2} ? How do you find cos( cot^{-1} sqrt{3} ) without a calculator? How do you rewrite sec^2 (tan^{-1} x) in terms of x? How do you use the inverse trigonometric properties to rewrite expressions in terms of x? How do you calculate sin^-1(0.1)? How do you solve the inverse trig function cos^-1 (-sqrt2/2)? How do you solve the inverse trig function sin(sin^-1 (1/3))? See all questions in Inverse Trigonometric Properties Impact of this question 3035 views around the world You can reuse this answer Creative Commons License