Question #e4dde

Question

1222 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-06-19T03:21:56

$1.56 xx 10^21$ $"atoms Na"$

$= 0.00259$ $"mol Na"$

$= 0.0596$ $"g Na"$

Your answer is in the question: $1.56 xx 10^21$ atoms of $"Na"$ is equal to $1.56 xx 10^21$ atoms of $"Na"$ .

If you would like to find the number of moles present, you can use Avogadro's number to find this:

$1.56 xx 10^21 cancel("atoms Na")((1color(white)(l)"mol Na")/(6.022 xx 10^23cancel("atoms Na")))$
$= color(red)(0.00259$ $color(red)("mol Na"$

You can also find the mass of sodium present, using the molar mass of sodium, $22.99"g"/"mol"$ (found on a periodic table):

$color(red)(0.00259$ $cancel(color(red)("mol Na"))((22.99color(white)(l)"g Na")/(1cancel("mol Na"))) = color(blue)(0.0596$ $color(blue)("g Na"$