Question

Question #b844d

Answer 1

`(10 mgNO_3)/(Liter)` = `((0.01gNO_3)/(1000g"Soln"))`

In each of the following, note how the ratio (in common units) is multiplied by the factor needed; that is,
=> pph = ratio x 100 => %
=> ppm = ratio x 1-million
=> ppb = ratio x 1-billion

=> `%NO_3` = Parts per Hundred = `((0.01gNO_3)/(1000g"Soln"))` x 100% = `1xx10^-3%(NO_3)` or `1xx10^-3` parts per hundred (pph)

=> Parts per Million `("ppm")` = `((0.01gNO_3)/(1000g"Soln"))` x `10^6("ppm")` = 10 ppm

=> Parts per Billion `("ppb")` = `((0.01gNO_3)/(1000g"Soln"))` x `10^9("ppb")` = 10000 ppb

=> Molarity(M) = `"moles"/"Liter"` = `((0.01gNO_3)/(62(g)/(mol)))(L^-1)` = `1.61xx10^-4M`