In one mole of glucose, how many oxygen atoms are present?

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In one mole of glucose, how many oxygen atoms are present?

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Answer 1 · 2017-07-02T08:47:13

In glucose, $C_{6} H_{12} O_{6}$ $C_6H_12O_6$ .....I gets $180.16 \cdot g$ $180.16*g$ of glucose.

Explanation:

$Moles of oxygen atoms$ $"Moles of oxygen atoms"$ $=$ $=$ $6 \times moles of glucose$ $6xx"moles of glucose"$ . Why? Because CLEARLY, each mole of glucose, $C_{6} H_{12} O_{6}$ $C_6H_12O_6$ contains $6 \cdot m o l$ $6*mol$ oxygen atoms.

Note that I am labouring the point that we deal with OXYGEN ATOMS , NOT OXYGEN MOLECULES.

$96 \cdot g$ $96*g$ oxygen is a molar quantity of $\frac{96 \cdot g}{16 \cdot g \cdot m o l^{- 1}} = 6 \cdot m o l$ $(96*g)/(16*g*mol^-1)=6*mol$ with respect to oxygen atoms.

And of course if there are $6 \cdot m o l$ $6*mol$ oxygen atoms, there must be $1 \cdot m o l$ $1*mol$ glucose. Agreed?

We are not quite finished because we were asked for the mass, and so we multiply the molar quantity by the molar mass of glucose.....

$1 \cdot m o l \times 180.16 \cdot g \cdot m o l^{- 1} = 180.16 \cdot g$ $1*molxx180.16*g*mol^-1=180.16*g$ .

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In one mole of glucose, how many oxygen atoms are present?

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