What is the molar quantity of sulfur in a $192 \cdot g$ $192*g$ mass of the element?

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What is the molar quantity of sulfur in a $192 \cdot g$ $192*g$ mass of the element?

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Answer 1 · 2017-07-06T06:05:34

Approx. $6 \cdot m o l$ $6*mol$

Explanation:

$Number of moles = \frac{Mass}{Molar mass} = \frac{192 \cdot g}{32.06 \cdot g \cdot m o l^{- 1}}$ $"Number of moles"="Mass"/"Molar mass"=(192*g)/(32.06*g*mol^-1)$

$= ? ? \cdot m o l$ $=??*mol$

Sulfur is probably present as the $S_{8}$ $S_8$ molecule. How many such molecules are present in the molar quantity?

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What is the molar quantity of sulfur in a $192 \cdot g$ $192*g$ mass of the element?

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What is the molar quantity of sulfur in a $192 \cdot g$ $192*g$ mass of the element?