The formula for molarity is
"molarity" = "mol solute"/"L soln"
We therefore need to find the number of moles of "HCl" and the number of liters of solution.
The moles of "HCl" is found via its molar mass (36.46 "g/mol"):
44.78cancel("g HCl")((1color(white)(l)"mol HCl")/(36.46cancel("g HCl"))) = color(red)(1.228 color(red)("mol HCl"
The number of liters of solution is
730.05cancel("mL")((1color(white)(l)"L")/(10^3cancel("mL"))) = color(green)(0.73005 color(green)("L"
Plugging these into the molarity equation, we have
"molarity" = (color(red)(1.228)color(white)(l)color(red)("mol"))/(color(green)(0.73005)color(white)(l)color(green)("L")) = color(blue)(1.682M