What is the mass of $12.04xx10^23$ $"formula units"$ of $MgCl_2$ ?

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Answer 1 · 2017-07-14T15:25:56

Well, we know that $6.022xx10^23$ $MgCl_2$ formula units have a mass of $95.21*g$ .......

Do we know this? All I have is taken the molar mass of magnesium chloride, and translated this into a NUMBER of magnesium chloride formula units...

And here we gots $12.04xx10^23$ $MgCl_2$ formula units.........

And thus we gots the product...........

$(12.04xx10^23*"formula units")/(6.022xx10^23*"formula units"*mol^-1)xx95.21*g*mol^-1$ ....

And I make this a mass of $190.42*g$ ........do you agree?

Is the product dimensionally consistent?

What is the mass of 12.04xx10^2312.04xx10^23 "formula units""formula units" of MgCl_2MgCl_2?