Question

Question #b1009

Answer 1

`"Molarity"="Moles of acid"/"Volume of soltion."`

And by the way you add acid to water, and never water to acid..

Explanation:

We have a molar quantity of ..........................

`7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1=3.28*mol` with respect to `HCl`.

And thus.............. `"Molarity"=(7.2*mol*L^-1xx455.2*mLxx10^-3*L*mL^-1)/(1270.0*L)`

`=2.258xx10^-3*mol*L^-1`