Question

Question #0cba7

Answer 1

The yield will be `2` `mol` of `H_2O`.

Explanation:

First we need to write a balanced chemical equation:

`2H_2+O_2=2H_2O`

In this case, the `O_2` will be the limiting reagent: we need `2` `mol` of `H_2` for each mole of `O_2`, but we have 4. There will be some `H_2` left over unreacted.

We know from the balanced equation that `1` `mol` of `O_2` will yield `2` `mol` of `H_2O`, and since we have `1` `mol` of `O_2` the yield will be `2` `mol` of `H_2O`.