A gas confined to a piston is subjected to a pressure that is THREE TIMES as great as the initial pressure. How does the volume evolve given constant temperature?

1 Answer
anor277
Jul 15, 2017

Should not the volume REDUCE to a third of the original volume?

Explanation:

Old Boyle's Law holds that PV=k at constant temperature and constant amount of gas......

And thus P_1V_1=P_2V_2..................given that we describe a piston containing the SAME amount of gas.........

And if we solve for V_2=(P_1V_1)/P_2=(P_1V_1)/(3P_1)=1/3*V_1 (because we specify that P_2=3xxP_1).

Does this make sense intuitively, given that we compress a gas at constant temperature?

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