Question

A gas occupies `"1.46 L"` at a pressure of `"1.00 bar"`. What is the volume when the gas is dropped into the ocean to a depth such that the pressure is increased to `"60.0 bar"`?

Answer 1

The final volume `(V_2)` is `"0.0243 L"`.

Refer to the explanation for the process.

Explanation:

This question involves Boyle's law, which states that the volume of a gas held at constant temperature varies inversely with the pressure. The means that if the volume increases, the pressure decreases, and vice versa. The equation for Boyle's law is:

`P_1V_1=P_2V_2`

Organize the data.

`P_1="1.00 bar"`

`V_1="1.46 L"`

`P_2="60.0 bar"`

`V_2="?"`

Solution

Rearrange the equation to isolate `V_2`. Substitute the data into the equation and solve.

`V_2=(P_1V_1)/P_2`

`V_2=(1.00color(red)cancel(color(black)("bar"))xx1.46"L")/(60.0color(red)cancel(color(black)("bar")))="0.0243 L"` (rounded to three significant figures)