What is the volume of $2 \cdot m o l$ $2mol$ of an Ideal Gas at $0$ $0$ $^{\circ} C$ $""^@C$ , and $1 \cdot a t m$ $1atm$ ?

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What is the volume of $2 \cdot m o l$ $2mol$ of an Ideal Gas at $0$ $0$ $^{\circ} C$ $""^@C$ , and $1 \cdot a t m$ $1atm$ ?

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Answer 1 · 2017-07-21T16:56:31

$4.54 \cdot 10^{- 2} m^{3}$ $4.54*10^(-2)m^3$

Explanation:

The ideal gas law says that, $p V = n R T$ $pV=nRT$ , where:
$p$ $p$ = pressure ( $P a$ $Pa$ )
$V$ $V$ = volume ( $m^{3}$ $m^3$ )
$n$ $n$ = number of moles ( $m o l$ $mol$ )
$R$ $R$ = gas constant, ( $8.31 J$ $8.31J$ $K^{- 1}$ $K^(-1)$ $m o l^{- 1}$ $mol^(-1)$ )
$T$ $T$ = temperature ( $K$ $K$ )

$1$ $1$ $a t m \approx 100000 P a$ $atm ~~ 100000Pa$
$0^{\circ} C \approx 273^{\circ} K$ $0^circC ~~ 273^circK$

$V = \frac{n R T}{P} = \frac{2 \cdot 8.31 \cdot 273}{100000} = 0.0453726 m^{3} \approx 0.0454 m^{3} = 4.54 \cdot 10^{- 2} m^{3}$ $V=(nRT)/P=(2*8.31*273)/100000=0.0453726m^3~~0.0454m^3=4.54*10^(-2)m^3$

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What is the volume of $2 \cdot m o l$ $2mol$ of an Ideal Gas at $0$ $0$ $^{\circ} C$ $""^@C$ , and $1 \cdot a t m$ $1atm$ ?

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