Question

How would the volume evolve if a `13000*L` of gas under a `1.38*atm` pressure were subjected to a `250*atm` pressure?

Answer 1

The new volume would have to be smaller.........

Explanation:

We use old Boyle's law, which holds that `Pprop1/V`

And thus `P=k/V`, where `k` is some constant.......and if we solve for `k` under different conditions of pressure and volume (but constant temperature), then..........

`P_1V_1=P_2V_2`....

And thus `V_2=(P_1V_1)/P_2=(1.38*atmxx13000*L)/(250*atm)`

`71.76*L`.

As regards the experimental setup, the experiment would have to be performed in a huge piston..... Perhaps the apparatus is not physically reasonable.