How many moles of $C_{6} H_{12} O_{6}$ $"C"_6"H"_12"O"_6"$ will be consumed if 6 moles of $O_{2}$ $"O"_2"$ are consumed?

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How many moles of $C_{6} H_{12} O_{6}$ $"C"_6"H"_12"O"_6"$ will be consumed if 6 moles of $O_{2}$ $"O"_2"$ are consumed?

$C_{6} H_{12} O_{6} + {6O}_{2}$ $"C"_6"H"_12"O"_6 + "6O"_2"$ $\to$ $rarr$ ${6CO}_{2} + {6H}_{2} O$ $"6CO"_2 +"6H"_2"O"$

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Answer 1 · 2017-07-25T01:13:23

One mole of $C_{6} H_{12} O_{6}$ $"C"_6"H"_12"O"_6$ will be consumed if ${6 mol O}_{2}$ $"6 mol O"_2$ are consumed.

Explanation:

Balanced Equation

$C_{6} H_{12} O_{6} + {6O}_{2}$ $"C"_6"H"_12"O"_6 + "6O"_2"$ $\to$ $rarr$ ${6CO}_{2} + {6H}_{2} O$ $"6CO"_2 +"6H"_2"O"$

The coefficients in a chemical equation indicate the number of moles of each element, molecule, or formula unit. In this equation, all of the substances are molecules. If there is no coefficient, it is understood to be $1$ $1$ .

The balanced equation shows us that 1 mole $C_{12} H_{2} O_{6}$ $"C"_12"H"_2"O"_6$ will be consumed if 6 moles $O_{2}$ $"O"_2$ are consumed.

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How many moles of $C_{6} H_{12} O_{6}$ $"C"_6"H"_12"O"_6"$ will be consumed if 6 moles of $O_{2}$ $"O"_2"$ are consumed?

$C_{6} H_{12} O_{6} + {6O}_{2}$ $"C"_6"H"_12"O"_6 + "6O"_2"$ $\to$ $rarr$ ${6CO}_{2} + {6H}_{2} O$ $"6CO"_2 +"6H"_2"O"$

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Explanation:

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How many moles of C6H12O6"C"_6"H"_12"O"_6" will be consumed if 6 moles of O2"O"_2" are consumed?

C6H12O6+6O2"C"_6"H"_12"O"_6 + "6O"_2"→rarr6CO2+6H2O"6CO"_2 +"6H"_2"O"

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How many moles of $C_{6} H_{12} O_{6}$ $"C"_6"H"_12"O"_6"$ will be consumed if 6 moles of $O_{2}$ $"O"_2"$ are consumed?

$C_{6} H_{12} O_{6} + {6O}_{2}$ $"C"_6"H"_12"O"_6 + "6O"_2"$ $\to$ $rarr$ ${6CO}_{2} + {6H}_{2} O$ $"6CO"_2 +"6H"_2"O"$