How many moles are in "1.68 g Fe"1.68 g Fe?

1 Answer
Jul 25, 2017

There is "0.0301 mol Fe"0.0301 mol Fe in "1.68 g Fe"1.68 g Fe.

There are 1.81xx10^221.81×1022 atoms in "1.68 g Fe"1.68 g Fe.

Explanation:

Divide the mass of iron by its molar mass in g/mol to get the moles of iron.

(1.68color(red)cancel(color(black)("g Fe")))/(55.845color(red)cancel(color(black)("g Fe"))/"mol Fe")="0.0301 mol Fe"

One mole of anything is 6.022xx10^23 of anything, including atoms. Multiply mol Fe by (6.022xx10^23)/("mol").

0.0301color(red)cancel(color(black)("mol Fe"))xx(6.022xx10^23"atoms Fe")/(1color(red)cancel(color(black)("mol Fe")))=1.81xx10^22 "atoms Fe" (rounded to three sig figs)