What is the volume occupied by a gas that has a 1000*mL1000⋅mL at 396*K396⋅K under 2*atm2⋅atm pressure, that is cooled to 200*K200⋅K, and the pressure decreased to 0.5*atm0.5⋅atm?

1 Answer
anor277
Jul 25, 2017

V_2~=8000*mLV2≅8000⋅mL as required........

Explanation:

(P_1V_1)/T_1=(P_2V_2)/T_2P1V1T1=P2V2T2, for a given quantity of gas according to the combined gas law.....

We solve for V_2=(P_1V_1T_2)/(P_2T_1)=??*mLV2=P1V1T2P2T1=??⋅mL

(2*atm*1000*mL*396*K)/(0.5*atm*200*K)=??*mL2⋅atm⋅1000⋅mL⋅396⋅K0.5⋅atm⋅200⋅K=??⋅mL....

Clearly we get an answer with units of volume as required. Do you agree? And remember 1*L-=1000*mL1⋅L≡1000⋅mL.

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