Question

Question #792b1

Answer 1

`"0.83 L"`

Explanation:

Molarity is all about the number of moles of solute and the volume of the solution expressed in liters, so start by using the 8molar mass* of calcium chloride to calculate the number of moles present in your sample.

`212 color(red)(cancel(color(black)("g"))) * "1 mole CaCl"_2/(110.98color(red)(cancel(color(black)("g")))) = "1.91 moles CaCl"_2`

Now, you know that in order to have a `"2.3-M"` solution of calcium chloride, you need to have `2.3` moles of calcium chloride for every `"1 L"` of solution.

Since solutions are homogeneous mixtures, i.e. they have the same composition throughout, you can use the molarity of the solution as a conversion factor to find the volume of solution that would contain `1.91` moles of solute.

`1.91 color(red)(cancel(color(black)("moles CaCl"_2))) * overbrace("1 L solution"/(2.3color(red)(cancel(color(black)("moles CaCl"_2)))))^(color(blue)("= 2.3 M")) = color(darkgreen)(ul(color(black)("0.83 L solution")))`

The answer is rounded to two sig figs, the number of significant figures you have for the molarity of the solution.